Short Problem Definition:

Calculate and print the sum of the elements in an array, keeping in mind that some of those integers may be quite large.

A Very Big Sum

Complexity:

time complexity is O(N)

space complexity is O(1)

Execution:

Just add all of this together. No magic.

Solution:
#!/usr/bin/py
if __name__ == '__main__':
    t = input()
    n = map(int, raw_input().split())
    print sum(n)

# RUST

use std::io;

fn get_number() -> u32 {
    let mut line = String::new();
    io::stdin().read_line(&mut line).ok().expect("Failed to read line");
    line.trim().parse::<u32>().unwrap()
}

fn get_numbers() -> Vec<u32> {
    let mut line = String::new();
    io::stdin().read_line(&mut line).ok().expect("Failed to read line");
    line.split_whitespace().map(|s| s.parse::<u32>().unwrap()).collect()
}

fn main() {
    get_number();  
    let sum = get_numbers().iter().fold(0u64, |a, &b| a + b as u64);
    println!("{}", sum)
}