Short Problem Definition:
There are N integers in an array A. All but one integer occur in pairs. Your task is to find out the number that occurs only once.
Link
Complexity:
time complexity is O(N)
space complexity is O(1)
Execution:
XORing two equal numbers cancels them out. XOR all numbers together.
Solution:
#!/usr/bin/py
def lonelyinteger(a):
    answer = 0
    for candidate in a:
        answer ^= candidate
    return answer
if __name__ == '__main__':
    a = input()
    b = map(int, raw_input().strip().split(" "))
    print lonelyinteger(b)
