##### Short Problem Definition:

Manasa is out on a hike with friends. She finds a trail of stones with numbers on them. She starts following the trail and notices that two consecutive stones have a difference of either aor b. Legend has it that there is a treasure trove at the end of the trail and if Manasa can guess the value of the last stone, the treasure would be hers. Given that the number on the first stone was 0, find all the possible values for the number on the last stone.

##### Link

##### Complexity:

time complexity is O(N);

space complexity is O(N)

##### Execution:

There are two distinct values. It is basically a combination with repetition. The order of the stones does not matter.

##### Solution:

#!/usr/bin/py def manasa(n, a, b): solutions = set() for i in xrange(n): solutions.add(a * i + b * (n-i-1)) return solutions if __name__ == '__main__': t = input() for _ in xrange(t): n = input() a = input() b = input() l = sorted(list(manasa(n, a, b))) print ' '.join(map(str, l))

If you enjoyed this post, then make sure you subscribe to my Newsletter and/or Feed.