# HackerRank ‘Pairs’ Solution

##### Short Problem Definition:

Given N integers, count the number of pairs of integers whose difference is K.

Pairs

##### Complexity:

time complexity is O(N*log(N))

space complexity is O(N)

##### Execution:

The solution is pretty straight-forward, just read the code :). The runtime complexity is calculated with log(N) access times for tree-based sets (not the case in Python).

##### Solution:
#!/usr/bin/py
def pairs(a,k):
s = set(a)
for v in s:
if v+k in s:

if __name__ == '__main__':
n, k = map(int, raw_input().split())
b = map(int, raw_input().split())
print pairs(b, k)


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