Short Problem Definition:
Alex is attending a Halloween party with his girlfriend Silvia. At the party, Silvia spots the corner of an infinite chocolate bar.
If the chocolate can be served as only 1 x 1 sized pieces and Alex can cut the chocolate bar exactly K times, what is the maximum number of chocolate pieces Alex can cut and give Silvia?
Link
Complexity:
time complexity is O(1);
space complexity is O(1)
Execution:
The product a*b (where a+b = k) is maximal, when a is close to b as possible. We can only use integral values, so a and b are rounded halves of k.
Solution:
#!/usr/bin/py def oneOneBars(K): half = K//2 return half * (K-half) if __name__ == '__main__': t = input() for _ in xrange(t): k = input() print oneOneBars(k)
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